Gujarati
Hindi
2. Electric Potential and Capacitance
medium

A capacitor stores $60\,\mu C$ charge when connected across a battery. When the gap between the plates is filled with dielectric, a charge of $120\,\mu C$ flows through the battery. The dielectric constant of the dielectric inserted is

A

$1$

B

$2$

C

$3$

D

$4$

Solution

$\mathrm{q}_{0}=\mathrm{C}_{0} \mathrm{V}$

$q=C V$ or $q=K C_{0} V$

$\therefore \mathrm{K}=\frac{\mathrm{q}}{\mathrm{q}_{0}}=\frac{120+60}{60}=3$

Because, the capacitor plates were initially charged to $60\, \mu C$ and on inserting the dielectric an additional charge of $120\, \mu \mathrm{C}$ also flows through the battery.

Standard 12
Physics

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